Wimbledon (H): Zverev facile

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As in his first match, Alexander Zverev qualified easily on Thursday for the third round, defeating Tennys Sandgren in three sets (7-5, 6-2, 6-3). The German will be opposed to another American, Fritz or Johnson, in the next round.

The matches follow and are similar for the moment for Alexander Zverev in this edition of Wimbledon. Already expeditious in the first round against the Dutchman Tallon Griekspoor (124th), ejected in three dry sets (6-3, 6-4, 6-1) and 1h34 of play, the German did not need to drag on either this Thursday for his second match of the tournament, against Tennys Sandgren (7-5, 6-2, 6-3, 1h47 of play).

Admittedly, the world number 6 had a little more difficulty getting started and finding the right fuel. But once launched, Zverev, never gone further in the event than the round of 16 (in 2017), no longer had any problem against the American who reached the quarterfinals of the Australian Open in twice (2018 and 2020) and who reached the round of 16 on London turf in 2019.

This time, the 68th in the standings will not see the third round, the fault of a Zverev who decided to leave only crumbs to his opponents until now. His next opponent and compatriot of Sandgren – the German will be opposed to Steve Johnson or Taylor Fritz – is warned.


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